Leif Karlsen, in his book Secrets of the Viking Navigators, gives a good argument that the Vikings used crystals of Iceland spar to ﬁnd the direction of the sun when just below the horizon or when obscured by fogbanks on the horizon, common at latitude 60° N where they did much of their ocean sailing. The technique he proposes works very well. We have done it many times using these Viking sunstones, which are readily available from gem shops online (you need a clear crystal, 1 to 2 inches on a side). This technique can pinpoint the direction to the sun to within a few degrees, and it was in fact used for many years in a more sophisticated arrangement as the basis of the Kollsman Sky Compass in the early days of polar exploration by air. Leif’s original instrument is still on display and the Nordic Heritage Museum, just around the corner from Starpath HQ. I had the pleasure of working with Leif on the project for many years. His study is the definitive work on the most likely way the device was actually used in Viking times, but we had to publish a special peer-reviewed article to confirm his right to this claim.
You can simulate the sunstone method with about the same precision using any polarized ﬁlm, such as the lenses of polarized sunglasses or some polarized camera ﬁlters. Some older sextant models also have polarized ﬁlters on the sunshades.
In addition to that, you need a small piece of cellophane. Many clear packaging tapes, the transparent windows of a CD sleeve, or the protective packaging of many products are often cellophane. On the other hand, some clear plastic products that look like cellophane, are actually another type of plastic and will not work for this application.
To prepare the lens, attach a piece of cellophane diagonally across the lens as shown in the left inset in the graphic below. Look through the lens with the cellophane on the far side (sky side) of the lens. The lines with the arrowheads in the ﬁgure represent the edge of the cellophane, crossing the middle of the lens.
In the video example, we used inexpensive polarized sunglasses that had no frame at all (Bartells in Ballard), it was just one piece of plastic formed into glasses. The we just cut them in half. I think we used the clear packing tape we get from U-line, and taped a strip across the glass diagonally as shown.
Then you want to hold this up and look at the sky through the glasses and tape (tape on the opposite side you are looking at), but you do not look in the direction you think the sun is—even without seeing it (already set or obscured) you know very roughly the direction to the sun. Rather, you want to hold this up in the direction that is 90º from that direction. In other words, it the sun had just set (roughly the case in the video), then you would be holding this up, looking directly overhead. For cases when the sun is overcast or behind clouds but not near the horizon, then you would look in a direction opposite to the sun at an angle from the sun as illustrated in the picture.
An important requirement is that this direction you are looking, i.e. 90º from the estimated sun direction, has to have some clear sky. If you look 90º from the sun and it too is covered by clouds, this will not work. Thee can be some level of overcast, but there must be some level of clear sky in that direction. The closer you are to looking at 90º to the actual sun, and the clearer the sky is in that direction, the better it will work.
The three center group of drawings in the picture above show what you will see when you are facing the proper direction of maximum polarization, directly opposite the true bearing to the sun. When the cellophane edge is perpendicular to the horizon, the lens will be the same shade on both sides (cellophane side and no-cellophane side). When you rotate it slightly to the right and left (that is a yawing motion), the sides will change brightness, as shown in the two ﬁgures adjacent to the center one. There are three groups of pictures here, we are talking now about the middle group, which is what you see when you are looking in the proper direction.
The two rotated views are shown to the right and left (in the center group), but they would actually be in the same position as the middle one, just rotated to the right or to the left. The video will illustrate what we actually see.
On the other hand, if you are not facing opposite the true direction to the sun, you will see what is shown on the right or left of the center ﬁgures. If you are facing to the right, the edge of the cellophane will lean right when the sides have the same brightness, as shown, and when facing to the left of the proper direction, you will see what is shown on the left.
In short you can find the direction to the sun even when pointed slightly wrong, but you will not get a good vertical line as shown in the middle group, which takes more judgement on locating the bearing on the horizon.
This is a subtle process that takes some practice… and patience. But once the procedure is grasped, it can then be repeated much more readily. The sequence is: Look in the approximate right direction and then in the approximate right elevation. Then, starting with the cellophane edge perpendicular to horizon, rotate the lens to ﬁnd the orientation of that edge line when the two sides are about the same brightness. When you are in about the right direction, the two sides will switch in brightness quite prominently—providing you do indeed have a polarized ﬁlter and true.
I have always found when using the sunstone or these glasses in a hand held mode—as opposed to the device Leif invented for using a mirror—that it is easier and more accurate to hold a ruler along side the crystal or in this case the polarized glasses. The ruler enhances your perception of the yawing motion for better precision. Also in the video I also used a mirror. I just held the ruler and glasses up in one hand overhead and looked at it with a mirror in my lap. These modifications are (very crudely) sketched in the pictures below. (I will improve these when we can.) Also shown below is an illustration of the right direction to look.
|You can try both methods to see what works best for you. Just looking up works fine and is likely best. We used the mirror just so someone could make the video.|
Here is the video showing an actual measurement. The screen caps preceding it below show what is meant by "right" and "wrong" heard in the video.
Here is the explanation that is printed in the video description:
This is just after sunset, with a bright patch on the horizon to locate sun direction as a test. It is using a mirror facing straight up to view the glasses that have a piece of cellophane tape pasted diagonally across the glass. This can be done without the mirror by looking straight up to the taped glasses, but i could not take a video of it that way. The video was taken with an iPhone.
This is a modern version of using polarized film (cheap clip-on sunglasses, cut in half) as a Viking sun stone (Icelandic Spar). It is a way to find the direction to the sun after it has set or when it might be behind a cloud bank. Maximum polarization is in a direction 90º from the sun direction, which is straight up with the sun near the horizon.
I am holding a meter stick along the edge of the cellophane tape to enhance the rotation angle, which helps pinpoint the direction.
When you watch the video, I am rotating the ruler and glasses to the right and left and noting which side is dark or light, and when the two sides are the same brightness, the the edge of the cellophane and in this case ruler are pointing to the sun... which was set below the horizon for some period of time as i was doing this. I was using a mirror in this case only so i could make the video, which would he hard to to looking up. In this case a friend was taking the video over my shoulder looking down at the mirror. Doing this on your own there is no need for a mirror. It just gets in the way. By the way, the obvious way to practice is do it (without a mirror as you can then see where you are pointed, and do it just at or after sunset so you know indeed what is the right answer.
|Too far right. One side is darker than the other.|
|Just right, both sides same color. The Ruler is pointed to the sun, even though the sun is not viable at the moment. It could be set (as in this case) or obscured behind a fogbank or clouds.|
|Too far Left. One side is darker than the other.|
----------------------------------------------- Here is the video -----------------------------------------------
A couple details (my guess is, no one wants more details at this point!)
This technique works because scattered sunlight is polarized. If you imagine a line straight up to your zenith and another line straight toward the sun, then these two lines deﬁne a plane. The electromagnetic oscillations within sunlight that have been scattered by air molecules are perpendicular to that plane, whereas in direct sunlight these oscillations are randomly distributed in all directions. Sunlight that has been reﬂected from a surface (glare from the water, for example) is also polarized, which is the motivation for polarized sunglasses. This light is horizontally polarized parallel to the reﬂecting surface, which means that sunglasses designed to block this glare are vertically polarized. An easy way to test that a pair of glasses is polarized is simply to look at such a reﬂective glare and rotate the glasses (looking straight through the lenses to the glare, roll the lenses, without pitch or yaw), and you should see the intensity of the glare change quite noticeably. On land you can do the same with bright glare from a window or car hood or bumper. When the glasses are working properly, you can see though the glare-producing windshield into the car; without them, or with your head turned 90°, you see only glare.
If you are using a lens of a pair of sunglasses, chances are the polarization axis is parallel to the bottom of the glasses, which means you will ﬁnd the brightest or darkest light transmission with the lens parallel or perpendicular to the horizon. If this is not the case, ﬁnd the best orientation and draw a line across the bottom of the lens when rotated into the darkest or brightest orientation—or mark the horizon with a piece of tape if you don’t have the right pen for the job.
When you attach the cellophane it should go diagonally across that axis. Once you have this "polarization compass" assembled, look again to the correct direction and rotate the device. You will notice now that the right and left sides alternate in brightness; when the two sides have the same level of brightness, the edge of the cellophane is pointing to the sun. The trick is to hunt around for the best direction; rotate the compass, note the sharpness, turn left a bit, try again, turn right and try again. When the angle is optimum, look up a bit and then down, etc.
As shown in Figure 8-4, you are ﬁnding a great-circle arc that points to the sun, so when looking to the left of the proper vertical plane, the line will point right, and when looking to the right of it, the line will point left.
Once you ﬁnd it with access to clear sky at 90º, the location of the brightness transition becomes very sharp. In short, this really works well.
After coming back to this video because of the several notifications we were getting here, I looked around at other videos online about the use of the sunstone itself. There are quite a few. They vary from almost right, to totally bizarre. I will try to get help and make a quick video of how to use an actual sunstone for this purpose. It is easier than this.
Thank you for your post, which i'll need to read again in order to grasp it correctly.
I've tried with no success to reproduce the way to locate (very approximately) the direction of the sun near the horizon with a calcite crystal. The only thing i can guess is when i detect polarized light and where the sun could be : on my right or on my left, when i'm looking into my cristal and detect polarized light. i can't tell on which side (in the hypothesis there is no other clue giving which side is the most probable). i have read somewhere - scientific paper - that one needs to use two crystals and two readings from 2 different positions, then find the intersection of 2 celestial circles... but i hope there is something simpler.
so... i would like to know if your method can tell on which side is the sun when you detect polarized light. Or if you use another clue to tell apart the 2 possibilities (ex. the horizon is clearer on one side, or you are making the experiment from a place where you already know very approximately where the sun should set, ...).
If you have a good stone, meaning clear enough to see the double refraction of a small piece of tape, then you should be able to find the sun very accurately. we have several more videos on the process that might help. See https://www.youtube.com/user/StarpathNav/playlists?view=1&flow=list
Thank you, a trove of videos :-)
the 4 videos i see that use a calcite crystal show favorable weather conditions (we see where the sun is approximately; we see from where the clouds are illuminated). Those conditions allow even me to decide which side is the sun with my calcite crystal; no problem...
what i can't do is decide where is the sun, only with the crystal, when there is no sunlight that is obviously coming from one side or the other of the sky / horizon... this being said, practically, this may almost never happen (read something, a bit old, basically based on that - figure 3 and 4 - https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3049005/ )
The sun stone can find the sun at sunset and sunrise when there is no indication at all from relative lighting. all that is needed is clear sky overhead. This was indeed the virtue of the procedure. needless to say at sunset the sun would be on the western horizon; run rise to the east. in the summer (declination +) this would be some degrees to the west of north by an amount = to the amplitude of the sun; in the winter it would be south of west. from a practical point of view it seems almost impossible to live through a day as a person who cares about navigation and not know broadly west vs east. ( if this is an issue for actual practice, then you can compute the bearing to the sun and start in that direction. ) Must have clear sky overhead... and you are looking directly overhead through the crystal to find the sun direction on the horizon.
To answer the question more directly, namely we assume that we do not know east from west and the sky is gray everywhere *except" overhead where it is clear. Then the trick to remember is the polarization is strongest at 90º from the sun. So do not wait till the sun is down on the horizon, but start when you think it might be some 20 or 30º above the horizon. Then do not look straight up at the zenith but instead look down from the zenith some 20-30º and look for the degree of polarization as you turn in a circle spanning the full horizon. You should see it peak out when the crystal axis points to the sun... or nearly there. could be off by 6º
Thank you very much;
my problem is exactly with "90° from the sun" ;
when i look in one direction, and my crystal says i'm looking "90 ° from the sun", i only know that the sun is 90° on my left, or 90° on my right ...
or is there something else that helps decide which side is the good one ?
You can use any square cardboard piece to be sure you are looking 90º from where you guess the sun is. Then do this facing north 000, then slowly turn, ie stay looking 90º from sun but now facing 015, then 030, then 045, etc all around the circle. You are thus scanning the full horizon.
To practice this, use the online program Astron ( https://friendsofthevigilance.org.uk/Astron/Astron.html ). Enter your lat and lon and the date. Find time of sunset, bottom right home page. Then set the time to be, say, 1 hour earlier (top orange line). Then go to top line of the Almanac page, and far right get the height of the sun Hc and its true bearing.
Here is a test case: Sat, july 25, 2020 from lat 48.0 N, 123.0 W, find the time of sunset to be 03 57 44 UTC, which is about 04 utc
then set the time to be 03z, and on the almanac page read: Hc = 7º 42.2' at true bearing 290.3º
so the peak polarization is 90º from that, which means looking 90º - 7º 42' above the horizon in direction 290+ 180... or look toward 110 at a height of about 82º
This can be done in the city in the back yard with no view at all to sun or horizon.
.... or to make it tons easier. Start when you can see the sun about 20º above the horizon and look in the other direction at about 70º above the horizon.... keeping in mind at all times that that this remains a subtle effect even with a good crystal and takes some concentration.
I hope this helps. It is all i can think of on this issue.
By the way, i note that this is the article about using sun glasses, but all that i am talking about is using a real crystal... not sunglasses. that is different... and i cannot pursue that part at the moment.
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